For this to happen by pure chance, that 8 randomly selected people from a group of 48 includes none of the 13 that are up for re-election, the odds are 6.2%. Not impossible but unlikely enough to doubt it’s a coincidence.
(For math people: this can be modeled as a hypergeometric distribution with N=48, K=13, n=8, k=0.)
For this to happen by pure chance, that 8 randomly selected people from a group of 48 includes none of the 13 that are up for re-election, the odds are 6.2%. Not impossible but unlikely enough to doubt it’s a coincidence.
(For math people: this can be modeled as a hypergeometric distribution with N=48, K=13, n=8, k=0.)